{"id":2185,"date":"2021-02-14T13:04:38","date_gmt":"2021-02-14T07:34:38","guid":{"rendered":"https:\/\/soulofmathematics.com\/?page_id=2185"},"modified":"2021-02-14T18:40:56","modified_gmt":"2021-02-14T13:10:56","slug":"greens-function","status":"publish","type":"page","link":"https:\/\/soulofmathematics.com\/index.php\/greens-function\/","title":{"rendered":"GREEN&#8217;S FUNCTION"},"content":{"rendered":"\n<figure class=\"wp-block-pullquote\"><blockquote><p>Green&#8217;s functions are named after the British&nbsp;mathematician <a href=\"https:\/\/en.wikipedia.org\/wiki\/George_Green_(mathematician)\">George Green<\/a>, who first developed the concept in the 1820s. In the modern study of linear&nbsp;partial differential equations, Green&#8217;s functions are studied largely from the point of view of&nbsp;fundamental solutions&nbsp;instead.<\/p><\/blockquote><\/figure>\n\n\n\n<p><\/p>\n\n\n\n<div class=\"wp-block-media-text alignwide is-stacked-on-mobile\" style=\"grid-template-columns:27% auto\"><figure class=\"wp-block-media-text__media\"><img data-recalc-dims=\"1\" fetchpriority=\"high\" decoding=\"async\" width=\"445\" height=\"561\" src=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/Screenshot__512_-removebg-preview.png?resize=445%2C561&#038;ssl=1\" alt=\"\" class=\"wp-image-2194 size-full\" srcset=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/Screenshot__512_-removebg-preview.png?w=445&amp;ssl=1 445w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/Screenshot__512_-removebg-preview.png?resize=238%2C300&amp;ssl=1 238w\" sizes=\"(max-width: 445px) 100vw, 445px\" \/><\/figure><div class=\"wp-block-media-text__content\">\n<blockquote class=\"wp-block-quote is-layout-flow wp-block-quote-is-layout-flow\"><p>The term is also used in&nbsp;physics, specifically in&nbsp;quantum field theory,&nbsp;aerodynamics,&nbsp;aeracoustics,&nbsp;electrodynamics, seismology&nbsp;and&nbsp;statistical field theory, to refer to various types of&nbsp;correlation functions, even those that do not fit the mathematical definition. In quantum field theory, Green&#8217;s functions take the roles of&nbsp;propagators.<\/p><\/blockquote>\n\n\n\n<p><\/p>\n<\/div><\/div>\n\n\n\n<h2 class=\"has-text-align-center wp-block-heading\">Preliminary ideas and motivation<\/h2>\n\n\n\n<h4 class=\"has-text-align-center wp-block-heading\">The delta function<\/h4>\n\n\n\n<p class=\"has-text-align-left\">Definition- The \u03b4-function is defined by the following three properties,<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter size-large is-resized\"><img data-recalc-dims=\"1\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-2.png?resize=259%2C183&#038;ssl=1\" alt=\"\" class=\"wp-image-2220\" width=\"259\" height=\"183\" srcset=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-2.png?w=812&amp;ssl=1 812w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-2.png?resize=300%2C212&amp;ssl=1 300w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-2.png?resize=768%2C544&amp;ssl=1 768w\" sizes=\"(max-width: 259px) 100vw, 259px\" \/><\/figure><\/div>\n\n\n\n<p>where f is continuous at x = a. The last is called the shifting property of the \u03b4-function. To make proofs with the \u03b4-function more rigorous, we consider a \u03b4-sequence, that is, a sequence of functions that converge to the \u03b4-function, at least in a pointwise sense. Consider the sequence<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter size-large is-resized\"><img data-recalc-dims=\"1\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-3.png?resize=195%2C54&#038;ssl=1\" alt=\"\" class=\"wp-image-2225\" width=\"195\" height=\"54\" srcset=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-3.png?w=556&amp;ssl=1 556w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-3.png?resize=300%2C83&amp;ssl=1 300w\" sizes=\"(max-width: 195px) 100vw, 195px\" \/><\/figure><\/div>\n\n\n\n<p>Note that,<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter size-large is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-4.png?resize=588%2C71&#038;ssl=1\" alt=\"\" class=\"wp-image-2228\" width=\"588\" height=\"71\" srcset=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-4.png?resize=1024%2C125&amp;ssl=1 1024w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-4.png?resize=300%2C36&amp;ssl=1 300w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-4.png?resize=768%2C93&amp;ssl=1 768w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-4.png?resize=1536%2C187&amp;ssl=1 1536w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-4.png?resize=1140%2C139&amp;ssl=1 1140w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-4.png?w=1792&amp;ssl=1 1792w\" sizes=\"(max-width: 588px) 100vw, 588px\" \/><\/figure><\/div>\n\n\n\n<p>The 2D \u03b4-function is defined by the following three properties,<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter size-large is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-5.png?resize=387%2C175&#038;ssl=1\" alt=\"\" class=\"wp-image-2230\" width=\"387\" height=\"175\" srcset=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-5.png?resize=1024%2C466&amp;ssl=1 1024w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-5.png?resize=300%2C136&amp;ssl=1 300w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-5.png?resize=768%2C349&amp;ssl=1 768w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-5.png?resize=1140%2C518&amp;ssl=1 1140w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-5.png?w=1249&amp;ssl=1 1249w\" sizes=\"(max-width: 387px) 100vw, 387px\" \/><\/figure><\/div>\n\n\n\n<div class=\"wp-block-image is-style-default\"><figure class=\"aligncenter size-large is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/greenEta-1.gif?resize=429%2C256&#038;ssl=1\" alt=\"\" class=\"wp-image-2269\" width=\"429\" height=\"256\"\/><\/figure><\/div>\n\n\n\n<h2 class=\"has-text-align-center wp-block-heading\">Finding the Green\u2019s function<\/h2>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<div class=\"wp-block-columns is-layout-flex wp-container-core-columns-is-layout-9d6595d7 wp-block-columns-is-layout-flex\">\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<p>To find the Green\u2019s function for a 2D domain D, we first find the simplest function that satisfies \u22072v = \u03b4(r). Suppose that v (x, y) is axis-symmetric, that is, v = v (r). Then<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter size-large is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-9.png?resize=224%2C70&#038;ssl=1\" alt=\"\" class=\"wp-image-2254\" width=\"224\" height=\"70\" srcset=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-9.png?w=470&amp;ssl=1 470w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-9.png?resize=300%2C94&amp;ssl=1 300w\" sizes=\"(max-width: 224px) 100vw, 224px\" \/><\/figure><\/div>\n\n\n\n<p>For r &gt; 0,<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter size-large is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-10.png?resize=163%2C67&#038;ssl=1\" alt=\"\" class=\"wp-image-2256\" width=\"163\" height=\"67\" srcset=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-10.png?w=317&amp;ssl=1 317w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-10.png?resize=300%2C123&amp;ssl=1 300w\" sizes=\"(max-width: 163px) 100vw, 163px\" \/><\/figure><\/div>\n\n\n\n<p>Integrating gives<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter size-large is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-11.png?resize=146%2C28&#038;ssl=1\" alt=\"\" class=\"wp-image-2257\" width=\"146\" height=\"28\"\/><\/figure><\/div>\n\n\n\n<p>For simplicity, we set B = 0. To find A, we integrate over a disc of radius \u03b5 centered at(x, y),D\u03b5,<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter size-large is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-12.png?resize=312%2C63&#038;ssl=1\" alt=\"\" class=\"wp-image-2258\" width=\"312\" height=\"63\" srcset=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-12.png?w=698&amp;ssl=1 698w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-12.png?resize=300%2C61&amp;ssl=1 300w\" sizes=\"(max-width: 312px) 100vw, 312px\" \/><\/figure><\/div>\n\n\n\n<p>From the Divergence Theorem, we have<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter size-large is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-13.png?resize=245%2C71&#038;ssl=1\" alt=\"\" class=\"wp-image-2259\" width=\"245\" height=\"71\" srcset=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-13.png?w=552&amp;ssl=1 552w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-13.png?resize=300%2C87&amp;ssl=1 300w\" sizes=\"(max-width: 245px) 100vw, 245px\" \/><\/figure><\/div>\n\n\n\n<p>where C\u03b5 is the boundary of D\u03b5, i.e. a circle of circumference 2\u03c0\u03b5. Combining the previous two equations gives<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter size-large is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-14.png?resize=438%2C65&#038;ssl=1\" alt=\"\" class=\"wp-image-2260\" width=\"438\" height=\"65\" srcset=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-14.png?w=993&amp;ssl=1 993w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-14.png?resize=300%2C45&amp;ssl=1 300w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-14.png?resize=768%2C114&amp;ssl=1 768w\" sizes=\"(max-width: 438px) 100vw, 438px\" \/><\/figure><\/div>\n\n\n\n<p>Hence<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter size-large is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-15.png?resize=146%2C54&#038;ssl=1\" alt=\"\" class=\"wp-image-2261\" width=\"146\" height=\"54\" srcset=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-15.png?w=308&amp;ssl=1 308w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-15.png?resize=300%2C114&amp;ssl=1 300w\" sizes=\"(max-width: 146px) 100vw, 146px\" \/><\/figure><\/div>\n\n\n\n<p>This is called the fundamental solution for the Green\u2019s function of the Laplacian on 2D domains. For 3D domains, the fundamental solution for the Green\u2019s function of the Laplacian is \u22121\/(4\u03c0r), where r = (x \u2212 \u03be)<sup>2<\/sup> + (y \u2212 \u03b7)<sup>2<\/sup> + (z \u2212 \u03b6)<sup>2<\/sup>. The Green\u2019s function for the Laplacian on 2D domains is defined in terms of the corresponding fundamental solution,<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter size-large is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-16.png?resize=273%2C133&#038;ssl=1\" alt=\"\" class=\"wp-image-2263\" width=\"273\" height=\"133\" srcset=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-16.png?w=625&amp;ssl=1 625w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-16.png?resize=300%2C147&amp;ssl=1 300w\" sizes=\"(max-width: 273px) 100vw, 273px\" \/><\/figure><\/div>\n<\/div>\n<\/div>\n<\/div><\/div>\n\n\n\n<p>The term \u201cregular\u201d means that h is twice continuously differentiable in(\u03be, \u03b7)on D. Finding the Green\u2019s function G is reduced to finding a C2 function h on D that satisfies<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter size-large is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-17.png?resize=268%2C91&#038;ssl=1\" alt=\"\" class=\"wp-image-2265\" width=\"268\" height=\"91\" srcset=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-17.png?w=619&amp;ssl=1 619w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-17.png?resize=300%2C102&amp;ssl=1 300w\" sizes=\"(max-width: 268px) 100vw, 268px\" \/><\/figure><\/div>\n\n\n\n<p>The definition of G in terms of h gives the BVP for G. Thus, for 2D regions D, finding the Green\u2019s function for the Laplacian reduces to finding h.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Examples<\/h3>\n\n\n\n<figure class=\"wp-block-gallery columns-2 is-cropped wp-block-gallery-1 is-layout-flex wp-block-gallery-is-layout-flex\"><ul class=\"blocks-gallery-grid\"><li class=\"blocks-gallery-item\"><figure><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"502\" height=\"394\" src=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/3d-gallery-meshpolygons-removebg-preview-1.png?resize=502%2C394&#038;ssl=1\" alt=\"\" data-id=\"2275\" data-full-url=\"https:\/\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/3d-gallery-meshpolygons-removebg-preview-1.png\" data-link=\"https:\/\/soulofmathematics.com\/index.php\/greens-function\/3d-gallery-meshpolygons-removebg-preview-1\/\" class=\"wp-image-2275\" srcset=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/3d-gallery-meshpolygons-removebg-preview-1.png?w=502&amp;ssl=1 502w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/3d-gallery-meshpolygons-removebg-preview-1.png?resize=300%2C235&amp;ssl=1 300w\" sizes=\"(max-width: 502px) 100vw, 502px\" \/><\/figure><\/li><li class=\"blocks-gallery-item\"><figure><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"960\" height=\"591\" src=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-18.png?resize=960%2C591&#038;ssl=1\" alt=\"\" data-id=\"2274\" class=\"wp-image-2274\" srcset=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-18.png?resize=1024%2C630&amp;ssl=1 1024w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-18.png?resize=300%2C185&amp;ssl=1 300w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-18.png?resize=768%2C472&amp;ssl=1 768w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-18.png?resize=1140%2C701&amp;ssl=1 1140w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-18.png?w=1213&amp;ssl=1 1213w\" sizes=\"(max-width: 960px) 100vw, 960px\" \/><\/figure><\/li><\/ul><\/figure>\n\n\n\n<p>Plot of the Green\u2019s function G(x,y;\u03be,\u03b7)for the Laplacian operator in the upper half plane, for(x, y)=(\u221a2,\u221a2). <\/p>\n\n\n\n<p>(i) Full plane D = R2. There are no boundaries so h =0 will do, and<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter size-large is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-19.png?resize=334%2C53&#038;ssl=1\" alt=\"\" class=\"wp-image-2276\" width=\"334\" height=\"53\" srcset=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-19.png?w=768&amp;ssl=1 768w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-19.png?resize=300%2C48&amp;ssl=1 300w\" sizes=\"(max-width: 334px) 100vw, 334px\" \/><\/figure><\/div>\n\n\n\n<p>(ii)Half plane D = {(x, y): y&gt; 0}. We find G by introducing what is called an \u201cimage point\u201d (x, \u2212y) corresponding to(x, y). Let r be the distance from (\u03be,\u03b7) to (x, y)and r \u2032 the distance from(\u03be,\u03b7) to the image point(x,\u2212y),<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter size-large is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-20.png?resize=423%2C46&#038;ssl=1\" alt=\"\" class=\"wp-image-2277\" width=\"423\" height=\"46\" srcset=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-20.png?resize=1024%2C112&amp;ssl=1 1024w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-20.png?resize=300%2C33&amp;ssl=1 300w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-20.png?resize=768%2C84&amp;ssl=1 768w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-20.png?w=1052&amp;ssl=1 1052w\" sizes=\"(max-width: 423px) 100vw, 423px\" \/><\/figure><\/div>\n\n\n\n<figure class=\"wp-block-image size-large\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"960\" height=\"678\" src=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/greenGap.gif?resize=960%2C678&#038;ssl=1\" alt=\"\" class=\"wp-image-2285\"\/><\/figure>\n\n\n\n<h3 class=\"has-text-align-center wp-block-heading\">Conformal mapping and the Green\u2019s function<\/h3>\n\n\n\n<p>Conformal mapping allows us to extend the number of 2D regions for which Green\u2019s functions of the Laplacian \u2207<sup>2<\/sup>u can be found. We use complex notation, and let \u03b1 = x + iy be a fixed point in D and let z = \u03be + i\u03b7 be a variable point in D (what we\u2019re integrating over). If D is simply connected (a definition from complex analysis), then by the Riemann Mapping Theorem, there is a conformal map w (z)(analytic and one-to-one) from D into the unit disk, which maps \u03b1 to the origin, w (\u03b1) =0 and the boundary of D to the unit circle, |w (z)|=1for z \u2208\u2202D and0 \u2264|w (z)|&lt; 1 for z \u2208D\/\u2202D. The Greens function G is then given by<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter size-large is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-21.png?resize=164%2C61&#038;ssl=1\" alt=\"\" class=\"wp-image-2280\" width=\"164\" height=\"61\" srcset=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-21.png?w=365&amp;ssl=1 365w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-21.png?resize=300%2C112&amp;ssl=1 300w\" sizes=\"(max-width: 164px) 100vw, 164px\" \/><\/figure><\/div>\n\n\n\n<p>To see this, we need a few results from complex analysis. First, note that for z \u2208\u2202D, w (z)=0 so that G = 0. Also, since w (z)is1-1, w (z)&gt; 0for z = \u03b1. Thus, we<br>can write w (z) =(z \u2212\u03b1)n H(z) where H(z) is analytic and nonzero in D. Since w (z)is1-1, w \u2032 (z)&gt; 0 on D. Thus n =1. Hence w (z)=(z \u2212\u03b1)H(z) and<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter size-large is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-22.png?resize=147%2C51&#038;ssl=1\" alt=\"\" class=\"wp-image-2281\" width=\"147\" height=\"51\" srcset=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-22.png?w=352&amp;ssl=1 352w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-22.png?resize=300%2C104&amp;ssl=1 300w\" sizes=\"(max-width: 147px) 100vw, 147px\" \/><\/figure><\/div>\n\n\n\n<p>where,<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter size-large is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-23.png?resize=315%2C87&#038;ssl=1\" alt=\"\" class=\"wp-image-2282\" width=\"315\" height=\"87\" srcset=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-23.png?w=741&amp;ssl=1 741w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2021\/02\/image-23.png?resize=300%2C83&amp;ssl=1 300w\" sizes=\"(max-width: 315px) 100vw, 315px\" \/><\/figure><\/div>\n\n\n\n<p>Since H(z) is analytic and nonzero in D, then (1\/2\u03c0) lnH(z) is analytic in D and hence its real part is harmonic, i.e. h = \u211c ((1\/2\u03c0) lnH(z)) satisfies \u22072h =0in D. Thus by our definition above, G is the Green\u2019s function of the Laplacian on D.<\/p>\n\n\n\n<div class=\"wp-block-buttons is-layout-flex wp-block-buttons-is-layout-flex\">\n<div class=\"wp-block-button\"><a class=\"wp-block-button__link has-black-color has-very-light-gray-to-cyan-bluish-gray-gradient-background has-text-color has-background\" href=\"https:\/\/simonverret.github.io\/\" target=\"_blank\" rel=\"noreferrer noopener\">IMAGE COUTESY<\/a><\/div>\n<\/div>\n\n\n\n<pre class=\"wp-block-preformatted\">NO COPYRIGHT INFRINGEMENT INTENDED<\/pre>\n","protected":false},"excerpt":{"rendered":"<p>Green&#8217;s functions are named after the British&nbsp;mathematician George Green, who first developed the concept in the 1820s. In the modern study of linear&nbsp;partial differential equations, Green&#8217;s functions are studied largely from the point of view of&nbsp;fundamental solutions&nbsp;instead. The term is also used in&nbsp;physics, specifically in&nbsp;quantum field theory,&nbsp;aerodynamics,&nbsp;aeracoustics,&nbsp;electrodynamics, seismology&nbsp;and&nbsp;statistical field theory, to refer to various types of&nbsp;correlation functions, even those that do not fit the mathematical definition. In quantum field theory, Green&#8217;s functions take the roles of&nbsp;propagators. Preliminary ideas and motivation The delta function Definition- The \u03b4-function is defined by the following three properties, where f is continuous at x = a. The last is called the shifting property of the \u03b4-function. To make proofs with the \u03b4-function more rigorous, we consider a \u03b4-sequence, that is, a sequence of functions that converge to the \u03b4-function, at least in a pointwise sense. Consider the sequence Note that, The 2D \u03b4-function is defined by the following three properties, Finding the Green\u2019s function To find the Green\u2019s function for a 2D domain D, we first find the simplest function that satisfies \u22072v = \u03b4(r). Suppose that v (x, y) is axis-symmetric, that is, v = v (r). Then For r &gt; 0, Integrating gives For simplicity, we set B = 0. To find A, we integrate over a disc of radius \u03b5 centered at(x, y),D\u03b5, From the Divergence Theorem, we have where C\u03b5 is the boundary of D\u03b5, i.e. a circle of circumference 2\u03c0\u03b5. Combining the previous two equations gives Hence This is called the fundamental solution for the Green\u2019s function of the Laplacian on 2D domains. For 3D domains, the fundamental solution for the Green\u2019s function of the Laplacian is \u22121\/(4\u03c0r), where r = (x \u2212 \u03be)2 + (y \u2212 \u03b7)2 + (z \u2212 \u03b6)2. The Green\u2019s function for the Laplacian on 2D domains is defined in terms of the corresponding fundamental solution, The term \u201cregular\u201d means that h is twice continuously differentiable in(\u03be, \u03b7)on D. Finding the Green\u2019s function G is reduced to finding a C2 function h on D that satisfies The definition of G in terms of h gives the BVP for G. Thus, for 2D regions D, finding the Green\u2019s function for the Laplacian reduces to finding h. Examples Plot of the Green\u2019s function G(x,y;\u03be,\u03b7)for the Laplacian operator in the upper half plane, for(x, y)=(\u221a2,\u221a2). (i) Full plane D = R2. There are no boundaries so h =0 will do, and (ii)Half plane D = {(x, y): y&gt; 0}. We find G by introducing what is called an \u201cimage point\u201d (x, \u2212y) corresponding to(x, y). Let r be the distance from (\u03be,\u03b7) to (x, y)and r \u2032 the distance from(\u03be,\u03b7) to the image point(x,\u2212y), Conformal mapping and the Green\u2019s function Conformal mapping allows us to extend the number of 2D regions for which Green\u2019s functions of the Laplacian \u22072u can be found. We use complex notation, and let \u03b1 = x + iy be a fixed point in D and let z = \u03be + i\u03b7 be a variable point in D (what we\u2019re integrating over). If D is simply connected (a definition from complex analysis), then by the Riemann Mapping Theorem, there is a conformal map w (z)(analytic and one-to-one) from D into the unit disk, which maps \u03b1 to the origin, w (\u03b1) =0 and the boundary of D to the unit circle, |w (z)|=1for z \u2208\u2202D and0 \u2264|w (z)|&lt; 1 for z \u2208D\/\u2202D. The Greens function G is then given by To see this, we need a few results from complex analysis. First, note that for z \u2208\u2202D, w (z)=0 so that G = 0. Also, since w (z)is1-1, w (z)&gt; 0for z = \u03b1. Thus, wecan write w (z) =(z \u2212\u03b1)n H(z) where H(z) is analytic and nonzero in D. Since w (z)is1-1, w \u2032 (z)&gt; 0 on D. Thus n =1. Hence w (z)=(z \u2212\u03b1)H(z) and where, Since H(z) is analytic and nonzero in D, then (1\/2\u03c0) lnH(z) is analytic in D and hence its real part is harmonic, i.e. h = \u211c ((1\/2\u03c0) lnH(z)) satisfies \u22072h =0in D. Thus by our definition above, G is the Green\u2019s function of the Laplacian on D. NO COPYRIGHT INFRINGEMENT INTENDED<\/p>\n","protected":false},"author":1,"featured_media":2187,"parent":0,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"jetpack_post_was_ever_published":false,"footnotes":""},"class_list":["post-2185","page","type-page","status-publish","has-post-thumbnail","hentry"],"ams_acf":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v23.6 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>GREEN&#039;S FUNCTION - SOUL OF MATHEMATICS<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/soulofmathematics.com\/index.php\/greens-function\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"GREEN&#039;S FUNCTION - SOUL OF MATHEMATICS\" \/>\n<meta property=\"og:description\" content=\"Green&#8217;s functions are named after the British&nbsp;mathematician George Green, who first developed the concept in the 1820s. In the modern study of linear&nbsp;partial differential equations, Green&#8217;s functions are studied largely from the point of view of&nbsp;fundamental solutions&nbsp;instead. The term is also used in&nbsp;physics, specifically in&nbsp;quantum field theory,&nbsp;aerodynamics,&nbsp;aeracoustics,&nbsp;electrodynamics, seismology&nbsp;and&nbsp;statistical field theory, to refer to various types of&nbsp;correlation functions, even those that do not fit the mathematical definition. In quantum field theory, Green&#8217;s functions take the roles of&nbsp;propagators. Preliminary ideas and motivation The delta function Definition- The \u03b4-function is defined by the following three properties, where f is continuous at x = a. The last is called the shifting property of the \u03b4-function. To make proofs with the \u03b4-function more rigorous, we consider a \u03b4-sequence, that is, a sequence of functions that converge to the \u03b4-function, at least in a pointwise sense. Consider the sequence Note that, The 2D \u03b4-function is defined by the following three properties, Finding the Green\u2019s function To find the Green\u2019s function for a 2D domain D, we first find the simplest function that satisfies \u22072v = \u03b4(r). Suppose that v (x, y) is axis-symmetric, that is, v = v (r). Then For r &gt; 0, Integrating gives For simplicity, we set B = 0. To find A, we integrate over a disc of radius \u03b5 centered at(x, y),D\u03b5, From the Divergence Theorem, we have where C\u03b5 is the boundary of D\u03b5, i.e. a circle of circumference 2\u03c0\u03b5. Combining the previous two equations gives Hence This is called the fundamental solution for the Green\u2019s function of the Laplacian on 2D domains. For 3D domains, the fundamental solution for the Green\u2019s function of the Laplacian is \u22121\/(4\u03c0r), where r = (x \u2212 \u03be)2 + (y \u2212 \u03b7)2 + (z \u2212 \u03b6)2. The Green\u2019s function for the Laplacian on 2D domains is defined in terms of the corresponding fundamental solution, The term \u201cregular\u201d means that h is twice continuously differentiable in(\u03be, \u03b7)on D. Finding the Green\u2019s function G is reduced to finding a C2 function h on D that satisfies The definition of G in terms of h gives the BVP for G. Thus, for 2D regions D, finding the Green\u2019s function for the Laplacian reduces to finding h. Examples Plot of the Green\u2019s function G(x,y;\u03be,\u03b7)for the Laplacian operator in the upper half plane, for(x, y)=(\u221a2,\u221a2). (i) Full plane D = R2. There are no boundaries so h =0 will do, and (ii)Half plane D = {(x, y): y&gt; 0}. We find G by introducing what is called an \u201cimage point\u201d (x, \u2212y) corresponding to(x, y). Let r be the distance from (\u03be,\u03b7) to (x, y)and r \u2032 the distance from(\u03be,\u03b7) to the image point(x,\u2212y), Conformal mapping and the Green\u2019s function Conformal mapping allows us to extend the number of 2D regions for which Green\u2019s functions of the Laplacian \u22072u can be found. We use complex notation, and let \u03b1 = x + iy be a fixed point in D and let z = \u03be + i\u03b7 be a variable point in D (what we\u2019re integrating over). If D is simply connected (a definition from complex analysis), then by the Riemann Mapping Theorem, there is a conformal map w (z)(analytic and one-to-one) from D into the unit disk, which maps \u03b1 to the origin, w (\u03b1) =0 and the boundary of D to the unit circle, |w (z)|=1for z \u2208\u2202D and0 \u2264|w (z)|&lt; 1 for z \u2208D\/\u2202D. The Greens function G is then given by To see this, we need a few results from complex analysis. First, note that for z \u2208\u2202D, w (z)=0 so that G = 0. Also, since w (z)is1-1, w (z)&gt; 0for z = \u03b1. Thus, wecan write w (z) =(z \u2212\u03b1)n H(z) where H(z) is analytic and nonzero in D. Since w (z)is1-1, w \u2032 (z)&gt; 0 on D. Thus n =1. Hence w (z)=(z \u2212\u03b1)H(z) and where, Since H(z) is analytic and nonzero in D, then (1\/2\u03c0) lnH(z) is analytic in D and hence its real part is harmonic, i.e. h = \u211c ((1\/2\u03c0) lnH(z)) satisfies \u22072h =0in D. Thus by our definition above, G is the Green\u2019s function of the Laplacian on D. 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In the modern study of linear&nbsp;partial differential equations, Green&#8217;s functions are studied largely from the point of view of&nbsp;fundamental solutions&nbsp;instead. The term is also used in&nbsp;physics, specifically in&nbsp;quantum field theory,&nbsp;aerodynamics,&nbsp;aeracoustics,&nbsp;electrodynamics, seismology&nbsp;and&nbsp;statistical field theory, to refer to various types of&nbsp;correlation functions, even those that do not fit the mathematical definition. In quantum field theory, Green&#8217;s functions take the roles of&nbsp;propagators. Preliminary ideas and motivation The delta function Definition- The \u03b4-function is defined by the following three properties, where f is continuous at x = a. The last is called the shifting property of the \u03b4-function. To make proofs with the \u03b4-function more rigorous, we consider a \u03b4-sequence, that is, a sequence of functions that converge to the \u03b4-function, at least in a pointwise sense. Consider the sequence Note that, The 2D \u03b4-function is defined by the following three properties, Finding the Green\u2019s function To find the Green\u2019s function for a 2D domain D, we first find the simplest function that satisfies \u22072v = \u03b4(r). Suppose that v (x, y) is axis-symmetric, that is, v = v (r). Then For r &gt; 0, Integrating gives For simplicity, we set B = 0. To find A, we integrate over a disc of radius \u03b5 centered at(x, y),D\u03b5, From the Divergence Theorem, we have where C\u03b5 is the boundary of D\u03b5, i.e. a circle of circumference 2\u03c0\u03b5. Combining the previous two equations gives Hence This is called the fundamental solution for the Green\u2019s function of the Laplacian on 2D domains. For 3D domains, the fundamental solution for the Green\u2019s function of the Laplacian is \u22121\/(4\u03c0r), where r = (x \u2212 \u03be)2 + (y \u2212 \u03b7)2 + (z \u2212 \u03b6)2. The Green\u2019s function for the Laplacian on 2D domains is defined in terms of the corresponding fundamental solution, The term \u201cregular\u201d means that h is twice continuously differentiable in(\u03be, \u03b7)on D. Finding the Green\u2019s function G is reduced to finding a C2 function h on D that satisfies The definition of G in terms of h gives the BVP for G. Thus, for 2D regions D, finding the Green\u2019s function for the Laplacian reduces to finding h. Examples Plot of the Green\u2019s function G(x,y;\u03be,\u03b7)for the Laplacian operator in the upper half plane, for(x, y)=(\u221a2,\u221a2). (i) Full plane D = R2. There are no boundaries so h =0 will do, and (ii)Half plane D = {(x, y): y&gt; 0}. We find G by introducing what is called an \u201cimage point\u201d (x, \u2212y) corresponding to(x, y). Let r be the distance from (\u03be,\u03b7) to (x, y)and r \u2032 the distance from(\u03be,\u03b7) to the image point(x,\u2212y), Conformal mapping and the Green\u2019s function Conformal mapping allows us to extend the number of 2D regions for which Green\u2019s functions of the Laplacian \u22072u can be found. We use complex notation, and let \u03b1 = x + iy be a fixed point in D and let z = \u03be + i\u03b7 be a variable point in D (what we\u2019re integrating over). If D is simply connected (a definition from complex analysis), then by the Riemann Mapping Theorem, there is a conformal map w (z)(analytic and one-to-one) from D into the unit disk, which maps \u03b1 to the origin, w (\u03b1) =0 and the boundary of D to the unit circle, |w (z)|=1for z \u2208\u2202D and0 \u2264|w (z)|&lt; 1 for z \u2208D\/\u2202D. The Greens function G is then given by To see this, we need a few results from complex analysis. First, note that for z \u2208\u2202D, w (z)=0 so that G = 0. Also, since w (z)is1-1, w (z)&gt; 0for z = \u03b1. Thus, wecan write w (z) =(z \u2212\u03b1)n H(z) where H(z) is analytic and nonzero in D. Since w (z)is1-1, w \u2032 (z)&gt; 0 on D. Thus n =1. Hence w (z)=(z \u2212\u03b1)H(z) and where, Since H(z) is analytic and nonzero in D, then (1\/2\u03c0) lnH(z) is analytic in D and hence its real part is harmonic, i.e. h = \u211c ((1\/2\u03c0) lnH(z)) satisfies \u22072h =0in D. Thus by our definition above, G is the Green\u2019s function of the Laplacian on D. 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