{"id":1296,"date":"2020-09-07T11:59:45","date_gmt":"2020-09-07T06:29:45","guid":{"rendered":"https:\/\/soulofmathematics.com\/?page_id=1296"},"modified":"2021-07-13T12:15:08","modified_gmt":"2021-07-13T06:45:08","slug":"lagranges-equation","status":"publish","type":"page","link":"https:\/\/soulofmathematics.com\/index.php\/lagranges-equation\/","title":{"rendered":"LAGRANGE&#8217;S EQUATION"},"content":{"rendered":"\n<blockquote class=\"wp-block-quote is-layout-flow wp-block-quote-is-layout-flow\"><p>As long as algebra and geometry have been separated, their progress have been slow and their uses limited; but when these two sciences have been united, they have lent each mutual forces, and have marched together towards perfection.<\/p><cite>Joseph-Louis Lagrange<\/cite><\/blockquote>\n\n\n\n<p>Partial  differential equations can be formed by the elimination of arbitrary constants or arbitrary functions. If we have <em>f (x, y)<\/em> then we have the following representation of partial derivatives,<\/p>\n\n\n\n<figure class=\"wp-block-image size-large is-resized\"><img data-recalc-dims=\"1\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-2.png?resize=662%2C75&#038;ssl=1\" alt=\"\" class=\"wp-image-1307\" width=\"662\" height=\"75\" srcset=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-2.png?resize=1024%2C117&amp;ssl=1 1024w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-2.png?resize=300%2C34&amp;ssl=1 300w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-2.png?resize=768%2C88&amp;ssl=1 768w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-2.png?resize=1536%2C175&amp;ssl=1 1536w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-2.png?resize=1140%2C130&amp;ssl=1 1140w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-2.png?w=1551&amp;ssl=1 1551w\" sizes=\"(max-width: 662px) 100vw, 662px\" \/><\/figure>\n\n\n\n<p>Let <em>F (x,y,z,p,q)<\/em> = 0 be the first order differential  equation. It contains three types of variables, where x and y are independent variables and z is dependent variable.<\/p>\n\n\n\n<p>A short classification of partial differential equations (PDE) &#8211;<\/p>\n\n\n\n<p><strong><em>Linear equation<\/em><\/strong>. A first order equation f (x, y, z, p, q) = 0 is known as linear if it is linear in p, q and z, that is, if given equation is of the form P(x, y) p + Q(x, y) q = R(x, y) z + S(x, y).<br><em>For example<\/em>, yx<sup>2<\/sup>p + xy<sup>2<\/sup>q = xyz + x<sup>2<\/sup>y<sup>3<\/sup> and p + q = z + xy are both first order linear partial differential equations.<br><strong><em>Semi-linear equation<\/em><\/strong>. A first order partial differential equation f (x, y, z, p, q) = 0 is known as a semi-linear equation, if it is linear in p and q and the coefficients of p and q are functions of x and y only i.e. if the given equation is of the form P(x, y) p + Q(x, y) q = R(x, y, z)<br><em>For example<\/em>, xyp + x<sup>2<\/sup>yq = x<sup>2<\/sup>y<sup>2<\/sup>z<sup>2<\/sup> and yp + xq = (x<sup>2<\/sup>z<sup>2<\/sup>\/y<sup>2<\/sup>) are both first order semi-linear partial differential equations.<br><strong><em>Quasi-linear equation<\/em><\/strong>. A first order partial differential equation f(x, y, z, p, q) = 0 is known as quasi-linear equation, if it is linear in p and q, i.e., if the given equation is of the form P(x, y, z) p + Q(x, y, z) q = R(x, y, z)<br><em>For example<\/em>, x<sup>2<\/sup>zp + y<sup>2<\/sup>zp = xy and (x<sup>2<\/sup> \u2013 yz) p + (y<sup>2<\/sup> \u2013 zx) q = z<sup>2<\/sup> \u2013 xy are first order quasi-linear partial differential equations.<br><strong><em>Non-linear equation<\/em><\/strong>. A first order partial differential equation f(x, y, z, p, q) = 0 which does not come under the above three types, in known as a non-liner equation.<br><em>For example<\/em>, p<sup>2<\/sup> + q<sup>2<\/sup> = 1, p q = z and x<sup>2<\/sup> p<sup>2<\/sup> + y<sup>2<\/sup> q<sup>2<\/sup> = z<sup>2<\/sup> are all non-linear partial differential equations.<\/p>\n\n\n\n<h3 class=\"has-text-align-center wp-block-heading\">THE EQUATION<\/h3>\n\n\n\n<p>A particular Quasi-linear partial differential equation of order one is of the form Pp + Qq = R, where P, Q and R are functions of x, y, z. Such a partial differential equation is known as Lagrange equation.<br>For Example xyp + yzq = zx is a Lagrange equation.<\/p>\n\n\n\n<p><strong>Theorem<\/strong>. The general solution of Lagrange equation Pp + Qq = R, is <\/p>\n\n\n\n<figure class=\"wp-block-image size-large is-resized\"><img data-recalc-dims=\"1\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-3.png?resize=90%2C20&#038;ssl=1\" alt=\"\" class=\"wp-image-1313\" width=\"90\" height=\"20\"\/><\/figure>\n\n\n\n<p>where \u0424 is an arbitrary function and u(x, y, z) = c<sub>1<\/sub> and v(x, y, z) = c<sub>2<\/sub> are two independent solutions of (<em>dx<\/em>)\/P = (<em>dy<\/em>)\/Q = (<em>dz<\/em>)\/R.                                          Here, c<sub>1<\/sub> and c<sub>2<\/sub> are arbitrary constants and at least one of u, v must contain z.<\/p>\n\n\n\n<p><strong>Proof<\/strong>. Lets number the equations for simplification.<\/p>\n\n\n\n<ol class=\"wp-block-list\"><li>Pp + Qq = R<\/li><li>\u0424(u, v) = 0<\/li><li>u(x, y, z) = c<sub>1<\/sub> and v(x, y, z) = c<sub>2<\/sub><\/li><li>(<em>dx<\/em>)\/P = (<em>dy<\/em>)\/Q = (<em>dz<\/em>)\/R<\/li><\/ol>\n\n\n\n<p>Differentiating (2) partially w.r.t. \u2018x\u2019 and \u2018y\u2019, we get equations 5 and 6,<\/p>\n\n\n\n<figure class=\"wp-block-image size-large is-resized\"><img data-recalc-dims=\"1\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-4.png?resize=304%2C67&#038;ssl=1\" alt=\"\" class=\"wp-image-1318\" width=\"304\" height=\"67\" srcset=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-4.png?w=710&amp;ssl=1 710w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-4.png?resize=300%2C66&amp;ssl=1 300w\" sizes=\"(max-width: 304px) 100vw, 304px\" \/><figcaption>and<\/figcaption><\/figure>\n\n\n\n<figure class=\"wp-block-image size-large is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-5.png?resize=314%2C67&#038;ssl=1\" alt=\"\" class=\"wp-image-1319\" width=\"314\" height=\"67\" srcset=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-5.png?w=721&amp;ssl=1 721w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-5.png?resize=300%2C64&amp;ssl=1 300w\" sizes=\"(max-width: 314px) 100vw, 314px\" \/><figcaption>respectively.<\/figcaption><\/figure>\n\n\n\n<p>Eliminating <strong>\u2202<\/strong>\u0424 \/ <strong>\u2202<\/strong>u and <strong>\u2202<\/strong>\u0424\/ <strong>\u2202<\/strong>v between (5) and (6), we have,<\/p>\n\n\n\n<figure class=\"wp-block-image size-large is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-6.png?resize=344%2C63&#038;ssl=1\" alt=\"\" class=\"wp-image-1321\" width=\"344\" height=\"63\" srcset=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-6.png?w=845&amp;ssl=1 845w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-6.png?resize=300%2C55&amp;ssl=1 300w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-6.png?resize=768%2C141&amp;ssl=1 768w\" sizes=\"(max-width: 344px) 100vw, 344px\" \/><figcaption>or,<\/figcaption><\/figure>\n\n\n\n<figure class=\"wp-block-image size-large is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-7.png?resize=407%2C62&#038;ssl=1\" alt=\"\" class=\"wp-image-1323\" width=\"407\" height=\"62\" srcset=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-7.png?resize=300%2C47&amp;ssl=1 300w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-7.png?zoom=2&amp;resize=407%2C62&amp;ssl=1 814w\" sizes=\"(max-width: 407px) 100vw, 407px\" \/><figcaption>or,<\/figcaption><\/figure>\n\n\n\n<figure class=\"wp-block-image size-large is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-8.png?resize=415%2C59&#038;ssl=1\" alt=\"\" class=\"wp-image-1324\" width=\"415\" height=\"59\" srcset=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-8.png?resize=1024%2C147&amp;ssl=1 1024w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-8.png?resize=300%2C43&amp;ssl=1 300w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-8.png?resize=768%2C110&amp;ssl=1 768w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-8.png?w=1100&amp;ssl=1 1100w\" sizes=\"(max-width: 415px) 100vw, 415px\" \/><\/figure>\n\n\n\n<p>Hence, (2) is a solution of this equation.<\/p>\n\n\n\n<p>Taking the differentials of u(x, y, z) = c<sub>1<\/sub> and v(x, y, z) = c<sub>2<\/sub>, we get,<\/p>\n\n\n\n<figure class=\"wp-block-image size-large is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-9.png?resize=295%2C28&#038;ssl=1\" alt=\"\" class=\"wp-image-1327\" width=\"295\" height=\"28\" srcset=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-9.png?w=765&amp;ssl=1 765w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-9.png?resize=300%2C29&amp;ssl=1 300w\" sizes=\"(max-width: 295px) 100vw, 295px\" \/><figcaption>and,<\/figcaption><\/figure>\n\n\n\n<figure class=\"wp-block-image size-large is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-10.png?resize=294%2C26&#038;ssl=1\" alt=\"\" class=\"wp-image-1329\" width=\"294\" height=\"26\" srcset=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-10.png?w=768&amp;ssl=1 768w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-10.png?resize=300%2C28&amp;ssl=1 300w\" sizes=\"(max-width: 294px) 100vw, 294px\" \/><\/figure>\n\n\n\n<p>As u and v are independent functions, the ratios dx : dy : dz, gives<\/p>\n\n\n\n<figure class=\"wp-block-image size-large is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-11.png?resize=357%2C71&#038;ssl=1\" alt=\"\" class=\"wp-image-1331\" width=\"357\" height=\"71\" srcset=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-11.png?w=978&amp;ssl=1 978w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-11.png?resize=300%2C60&amp;ssl=1 300w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-11.png?resize=768%2C155&amp;ssl=1 768w\" sizes=\"(max-width: 357px) 100vw, 357px\" \/><\/figure>\n\n\n\n<p>Comparing equations we obtain,<\/p>\n\n\n\n<figure class=\"wp-block-image size-large is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-12.png?resize=372%2C77&#038;ssl=1\" alt=\"\" class=\"wp-image-1332\" width=\"372\" height=\"77\" srcset=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-12.png?resize=1024%2C212&amp;ssl=1 1024w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-12.png?resize=300%2C62&amp;ssl=1 300w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-12.png?resize=768%2C159&amp;ssl=1 768w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-12.png?w=1041&amp;ssl=1 1041w\" sizes=\"(max-width: 372px) 100vw, 372px\" \/><\/figure>\n\n\n\n<p>We can imply that,<\/p>\n\n\n\n<figure class=\"wp-block-image size-large is-resized is-style-default\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-13.png?resize=155%2C60&#038;ssl=1\" alt=\"\" class=\"wp-image-1333\" width=\"155\" height=\"60\" srcset=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-13.png?w=391&amp;ssl=1 391w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-13.png?resize=300%2C116&amp;ssl=1 300w\" sizes=\"(max-width: 155px) 100vw, 155px\" \/><\/figure>\n\n\n\n<figure class=\"wp-block-image size-large is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-14.png?resize=157%2C52&#038;ssl=1\" alt=\"\" class=\"wp-image-1334\" width=\"157\" height=\"52\" srcset=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-14.png?w=403&amp;ssl=1 403w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-14.png?resize=300%2C100&amp;ssl=1 300w\" sizes=\"(max-width: 157px) 100vw, 157px\" \/><figcaption>and<\/figcaption><\/figure>\n\n\n\n<figure class=\"wp-block-image size-large is-resized\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-15.png?resize=155%2C52&#038;ssl=1\" alt=\"\" class=\"wp-image-1336\" width=\"155\" height=\"52\" srcset=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-15.png?w=402&amp;ssl=1 402w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/image-15.png?resize=300%2C100&amp;ssl=1 300w\" sizes=\"(max-width: 155px) 100vw, 155px\" \/><\/figure>\n\n\n\n<p>Substituting these values we get, k(Pp + Qq) = kR or Pp + Qq = R, which is the given equation (1). Therefore, if u(x, y, z) = c<sub>1<\/sub> and v(x, y, z) = c<sub>2<\/sub> are two independent solutions of the system of differential equations (dx)\/P = (dy)\/Q = (dz)\/R, then \u0424(u, v) = 0 is a solution of Pp + Qq = R, \u0424 being an arbitrary function.<\/p>\n\n\n\n<p><em>Equations (4) are called Lagrange\u2019s auxillary (or subsidiary) equations for (1).<\/em><\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter\"><img data-recalc-dims=\"1\" loading=\"lazy\" decoding=\"async\" width=\"497\" height=\"405\" src=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/436199_1_En_3_Fig11_HTML.png?resize=497%2C405&#038;ssl=1\" alt=\"\" class=\"wp-image-1341\" srcset=\"https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/436199_1_En_3_Fig11_HTML.png?w=497&amp;ssl=1 497w, https:\/\/i0.wp.com\/soulofmathematics.com\/wp-content\/uploads\/2020\/09\/436199_1_En_3_Fig11_HTML.png?resize=300%2C244&amp;ssl=1 300w\" sizes=\"(max-width: 497px) 100vw, 497px\" \/><figcaption>First Order Quasi-linear PDE<\/figcaption><\/figure><\/div>\n\n\n\n<h4 class=\"has-text-align-center wp-block-heading\">Steps for solving Pp + Qq = R by Lagrange\u2019s method.<\/h4>\n\n\n\n<p><strong><em>Step 1<\/em><\/strong>. Put the given linear partial differential equation of the first order in the standard form<br>Pp + Qq = R. \u2026(1)<br><strong><em>Step 2<\/em><\/strong>. Write down Lagrange\u2019s auxiliary equations for (1) namely,<br>(dx)\/P = (dy)\/Q = (dz)\/R \u2026(2)<br><strong><em>Step 3<\/em><\/strong>. Solve equation (2). Let u(x, y, z) = c<sub>1<\/sub> and v(x, y, z) = c<sub>2<\/sub> be two independent solutions of (2).<br><strong><em>Step 4<\/em><\/strong>. The general solution (or integral) of (1) is then written in one of the following three equivalent forms :<br>\u0424(u, v) = 0, u = \u0424(v) or v = \u0424(u), \u0424 being an arbitrary function.<\/p>\n\n\n\n<p>FOR TUTORIAL SHEETS AND REFINED MATERIALS SUBSCRIBE TO RECEIVE THEM VIA EMAIL.<\/p>\n\n\n\n<p><a rel=\"noreferrer noopener\" href=\"https:\/\/en.wikipedia.org\/wiki\/Partial_differential_equation#\/media\/File:Heat.gif\" data-type=\"URL\" data-id=\"https:\/\/en.wikipedia.org\/wiki\/Partial_differential_equation#\/media\/File:Heat.gif\" target=\"_blank\">IMAGE COURTESY<\/a><\/p>\n\n\n\n\t<div class=\"wp-block-jetpack-mailchimp\" data-blog-id=\"180998866\">\n\t\t<form\n\t\t\taria-describedby=\"wp-block-jetpack-mailchimp_consent-text\"\n\t\t\t\t\t>\n\t\t\t<p>\n\t\t\t\t<input\n\t\t\t\t\taria-label=\"Enter your email\"\n\t\t\t\t\tplaceholder=\"Enter your email\"\n\t\t\t\t\trequired\n\t\t\t\t\ttitle=\"Enter your email\"\n\t\t\t\t\ttype=\"email\"\n\t\t\t\t\tname=\"email\"\n\t\t\t\t\/>\n\t\t\t<\/p>\n\t\t\t\t\t\t\t\t\t\n<div class=\"wp-block-jetpack-button wp-block-button\" style=\"\"><button class=\"wp-block-button__link has-background has-cool-to-warm-spectrum-gradient-background\" style=\"\" data-id-attr=\"mailchimp-button-block-1\" id=\"mailchimp-button-block-1\" type=\"submit\">SUBSCRIBE<\/button><\/div>\n\t\t\t<p id=\"wp-block-jetpack-mailchimp_consent-text\">\n\t\t\t\t\t\t\t<\/p>\n\n\t\t\t\n\t\t<\/form>\n\t\t\n\t\t\t<div class=\"wp-block-jetpack-mailchimp_notification wp-block-jetpack-mailchimp_processing\" role=\"status\">\n\t\t\t\tProcessing\u2026\t\t\t<\/div>\n\t\t\t<div class=\"wp-block-jetpack-mailchimp_notification wp-block-jetpack-mailchimp_success\" role=\"status\">\n\t\t\t\tSuccess! You&#039;re on the list.\t\t\t<\/div>\n\t\t\t<div class=\"wp-block-jetpack-mailchimp_notification wp-block-jetpack-mailchimp_error\" role=\"alert\">\n\t\t\t\tWhoops! There was an error and we couldn&#039;t process your subscription. Please reload the page and try again.\t\t\t<\/div>\n\n\t\t\t<\/div>\n\t","protected":false},"excerpt":{"rendered":"<p>As long as algebra and geometry have been separated, their progress have been slow and their uses limited; but when these two sciences have been united, they have lent each mutual forces, and have marched together towards perfection. Joseph-Louis Lagrange Partial differential equations can be formed by the elimination of arbitrary constants or arbitrary functions. If we have f (x, y) then we have the following representation of partial derivatives, Let F (x,y,z,p,q) = 0 be the first order differential equation. It contains three types of variables, where x and y are independent variables and z is dependent variable. A short classification of partial differential equations (PDE) &#8211; Linear equation. A first order equation f (x, y, z, p, q) = 0 is known as linear if it is linear in p, q and z, that is, if given equation is of the form P(x, y) p + Q(x, y) q = R(x, y) z + S(x, y).For example, yx2p + xy2q = xyz + x2y3 and p + q = z + xy are both first order linear partial differential equations.Semi-linear equation. A first order partial differential equation f (x, y, z, p, q) = 0 is known as a semi-linear equation, if it is linear in p and q and the coefficients of p and q are functions of x and y only i.e. if the given equation is of the form P(x, y) p + Q(x, y) q = R(x, y, z)For example, xyp + x2yq = x2y2z2 and yp + xq = (x2z2\/y2) are both first order semi-linear partial differential equations.Quasi-linear equation. A first order partial differential equation f(x, y, z, p, q) = 0 is known as quasi-linear equation, if it is linear in p and q, i.e., if the given equation is of the form P(x, y, z) p + Q(x, y, z) q = R(x, y, z)For example, x2zp + y2zp = xy and (x2 \u2013 yz) p + (y2 \u2013 zx) q = z2 \u2013 xy are first order quasi-linear partial differential equations.Non-linear equation. A first order partial differential equation f(x, y, z, p, q) = 0 which does not come under the above three types, in known as a non-liner equation.For example, p2 + q2 = 1, p q = z and x2 p2 + y2 q2 = z2 are all non-linear partial differential equations. THE EQUATION A particular Quasi-linear partial differential equation of order one is of the form Pp + Qq = R, where P, Q and R are functions of x, y, z. Such a partial differential equation is known as Lagrange equation.For Example xyp + yzq = zx is a Lagrange equation. Theorem. The general solution of Lagrange equation Pp + Qq = R, is where \u0424 is an arbitrary function and u(x, y, z) = c1 and v(x, y, z) = c2 are two independent solutions of (dx)\/P = (dy)\/Q = (dz)\/R. Here, c1 and c2 are arbitrary constants and at least one of u, v must contain z. Proof. Lets number the equations for simplification. Pp + Qq = R \u0424(u, v) = 0 u(x, y, z) = c1 and v(x, y, z) = c2 (dx)\/P = (dy)\/Q = (dz)\/R Differentiating (2) partially w.r.t. \u2018x\u2019 and \u2018y\u2019, we get equations 5 and 6, Eliminating \u2202\u0424 \/ \u2202u and \u2202\u0424\/ \u2202v between (5) and (6), we have, Hence, (2) is a solution of this equation. Taking the differentials of u(x, y, z) = c1 and v(x, y, z) = c2, we get, As u and v are independent functions, the ratios dx : dy : dz, gives Comparing equations we obtain, We can imply that, Substituting these values we get, k(Pp + Qq) = kR or Pp + Qq = R, which is the given equation (1). Therefore, if u(x, y, z) = c1 and v(x, y, z) = c2 are two independent solutions of the system of differential equations (dx)\/P = (dy)\/Q = (dz)\/R, then \u0424(u, v) = 0 is a solution of Pp + Qq = R, \u0424 being an arbitrary function. Equations (4) are called Lagrange\u2019s auxillary (or subsidiary) equations for (1). Steps for solving Pp + Qq = R by Lagrange\u2019s method. Step 1. Put the given linear partial differential equation of the first order in the standard formPp + Qq = R. \u2026(1)Step 2. Write down Lagrange\u2019s auxiliary equations for (1) namely,(dx)\/P = (dy)\/Q = (dz)\/R \u2026(2)Step 3. Solve equation (2). Let u(x, y, z) = c1 and v(x, y, z) = c2 be two independent solutions of (2).Step 4. The general solution (or integral) of (1) is then written in one of the following three equivalent forms :\u0424(u, v) = 0, u = \u0424(v) or v = \u0424(u), \u0424 being an arbitrary function. FOR TUTORIAL SHEETS AND REFINED MATERIALS SUBSCRIBE TO RECEIVE THEM VIA EMAIL. 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Joseph-Louis Lagrange Partial differential equations can be formed by the elimination of arbitrary constants or arbitrary functions. If we have f (x, y) then we have the following representation of partial derivatives, Let F (x,y,z,p,q) = 0 be the first order differential equation. It contains three types of variables, where x and y are independent variables and z is dependent variable. A short classification of partial differential equations (PDE) &#8211; Linear equation. A first order equation f (x, y, z, p, q) = 0 is known as linear if it is linear in p, q and z, that is, if given equation is of the form P(x, y) p + Q(x, y) q = R(x, y) z + S(x, y).For example, yx2p + xy2q = xyz + x2y3 and p + q = z + xy are both first order linear partial differential equations.Semi-linear equation. A first order partial differential equation f (x, y, z, p, q) = 0 is known as a semi-linear equation, if it is linear in p and q and the coefficients of p and q are functions of x and y only i.e. if the given equation is of the form P(x, y) p + Q(x, y) q = R(x, y, z)For example, xyp + x2yq = x2y2z2 and yp + xq = (x2z2\/y2) are both first order semi-linear partial differential equations.Quasi-linear equation. A first order partial differential equation f(x, y, z, p, q) = 0 is known as quasi-linear equation, if it is linear in p and q, i.e., if the given equation is of the form P(x, y, z) p + Q(x, y, z) q = R(x, y, z)For example, x2zp + y2zp = xy and (x2 \u2013 yz) p + (y2 \u2013 zx) q = z2 \u2013 xy are first order quasi-linear partial differential equations.Non-linear equation. A first order partial differential equation f(x, y, z, p, q) = 0 which does not come under the above three types, in known as a non-liner equation.For example, p2 + q2 = 1, p q = z and x2 p2 + y2 q2 = z2 are all non-linear partial differential equations. THE EQUATION A particular Quasi-linear partial differential equation of order one is of the form Pp + Qq = R, where P, Q and R are functions of x, y, z. Such a partial differential equation is known as Lagrange equation.For Example xyp + yzq = zx is a Lagrange equation. Theorem. The general solution of Lagrange equation Pp + Qq = R, is where \u0424 is an arbitrary function and u(x, y, z) = c1 and v(x, y, z) = c2 are two independent solutions of (dx)\/P = (dy)\/Q = (dz)\/R. Here, c1 and c2 are arbitrary constants and at least one of u, v must contain z. Proof. Lets number the equations for simplification. Pp + Qq = R \u0424(u, v) = 0 u(x, y, z) = c1 and v(x, y, z) = c2 (dx)\/P = (dy)\/Q = (dz)\/R Differentiating (2) partially w.r.t. \u2018x\u2019 and \u2018y\u2019, we get equations 5 and 6, Eliminating \u2202\u0424 \/ \u2202u and \u2202\u0424\/ \u2202v between (5) and (6), we have, Hence, (2) is a solution of this equation. Taking the differentials of u(x, y, z) = c1 and v(x, y, z) = c2, we get, As u and v are independent functions, the ratios dx : dy : dz, gives Comparing equations we obtain, We can imply that, Substituting these values we get, k(Pp + Qq) = kR or Pp + Qq = R, which is the given equation (1). Therefore, if u(x, y, z) = c1 and v(x, y, z) = c2 are two independent solutions of the system of differential equations (dx)\/P = (dy)\/Q = (dz)\/R, then \u0424(u, v) = 0 is a solution of Pp + Qq = R, \u0424 being an arbitrary function. Equations (4) are called Lagrange\u2019s auxillary (or subsidiary) equations for (1). Steps for solving Pp + Qq = R by Lagrange\u2019s method. Step 1. Put the given linear partial differential equation of the first order in the standard formPp + Qq = R. \u2026(1)Step 2. Write down Lagrange\u2019s auxiliary equations for (1) namely,(dx)\/P = (dy)\/Q = (dz)\/R \u2026(2)Step 3. Solve equation (2). Let u(x, y, z) = c1 and v(x, y, z) = c2 be two independent solutions of (2).Step 4. The general solution (or integral) of (1) is then written in one of the following three equivalent forms :\u0424(u, v) = 0, u = \u0424(v) or v = \u0424(u), \u0424 being an arbitrary function. FOR TUTORIAL SHEETS AND REFINED MATERIALS SUBSCRIBE TO RECEIVE THEM VIA EMAIL. 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Joseph-Louis Lagrange Partial differential equations can be formed by the elimination of arbitrary constants or arbitrary functions. If we have f (x, y) then we have the following representation of partial derivatives, Let F (x,y,z,p,q) = 0 be the first order differential equation. It contains three types of variables, where x and y are independent variables and z is dependent variable. A short classification of partial differential equations (PDE) &#8211; Linear equation. A first order equation f (x, y, z, p, q) = 0 is known as linear if it is linear in p, q and z, that is, if given equation is of the form P(x, y) p + Q(x, y) q = R(x, y) z + S(x, y).For example, yx2p + xy2q = xyz + x2y3 and p + q = z + xy are both first order linear partial differential equations.Semi-linear equation. A first order partial differential equation f (x, y, z, p, q) = 0 is known as a semi-linear equation, if it is linear in p and q and the coefficients of p and q are functions of x and y only i.e. if the given equation is of the form P(x, y) p + Q(x, y) q = R(x, y, z)For example, xyp + x2yq = x2y2z2 and yp + xq = (x2z2\/y2) are both first order semi-linear partial differential equations.Quasi-linear equation. A first order partial differential equation f(x, y, z, p, q) = 0 is known as quasi-linear equation, if it is linear in p and q, i.e., if the given equation is of the form P(x, y, z) p + Q(x, y, z) q = R(x, y, z)For example, x2zp + y2zp = xy and (x2 \u2013 yz) p + (y2 \u2013 zx) q = z2 \u2013 xy are first order quasi-linear partial differential equations.Non-linear equation. A first order partial differential equation f(x, y, z, p, q) = 0 which does not come under the above three types, in known as a non-liner equation.For example, p2 + q2 = 1, p q = z and x2 p2 + y2 q2 = z2 are all non-linear partial differential equations. THE EQUATION A particular Quasi-linear partial differential equation of order one is of the form Pp + Qq = R, where P, Q and R are functions of x, y, z. Such a partial differential equation is known as Lagrange equation.For Example xyp + yzq = zx is a Lagrange equation. Theorem. The general solution of Lagrange equation Pp + Qq = R, is where \u0424 is an arbitrary function and u(x, y, z) = c1 and v(x, y, z) = c2 are two independent solutions of (dx)\/P = (dy)\/Q = (dz)\/R. Here, c1 and c2 are arbitrary constants and at least one of u, v must contain z. Proof. Lets number the equations for simplification. Pp + Qq = R \u0424(u, v) = 0 u(x, y, z) = c1 and v(x, y, z) = c2 (dx)\/P = (dy)\/Q = (dz)\/R Differentiating (2) partially w.r.t. \u2018x\u2019 and \u2018y\u2019, we get equations 5 and 6, Eliminating \u2202\u0424 \/ \u2202u and \u2202\u0424\/ \u2202v between (5) and (6), we have, Hence, (2) is a solution of this equation. Taking the differentials of u(x, y, z) = c1 and v(x, y, z) = c2, we get, As u and v are independent functions, the ratios dx : dy : dz, gives Comparing equations we obtain, We can imply that, Substituting these values we get, k(Pp + Qq) = kR or Pp + Qq = R, which is the given equation (1). Therefore, if u(x, y, z) = c1 and v(x, y, z) = c2 are two independent solutions of the system of differential equations (dx)\/P = (dy)\/Q = (dz)\/R, then \u0424(u, v) = 0 is a solution of Pp + Qq = R, \u0424 being an arbitrary function. Equations (4) are called Lagrange\u2019s auxillary (or subsidiary) equations for (1). Steps for solving Pp + Qq = R by Lagrange\u2019s method. Step 1. Put the given linear partial differential equation of the first order in the standard formPp + Qq = R. \u2026(1)Step 2. Write down Lagrange\u2019s auxiliary equations for (1) namely,(dx)\/P = (dy)\/Q = (dz)\/R \u2026(2)Step 3. Solve equation (2). Let u(x, y, z) = c1 and v(x, y, z) = c2 be two independent solutions of (2).Step 4. The general solution (or integral) of (1) is then written in one of the following three equivalent forms :\u0424(u, v) = 0, u = \u0424(v) or v = \u0424(u), \u0424 being an arbitrary function. FOR TUTORIAL SHEETS AND REFINED MATERIALS SUBSCRIBE TO RECEIVE THEM VIA EMAIL. 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