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<oembed><version>1.0</version><provider_name>SOUL OF MATHEMATICS</provider_name><provider_url>https://soulofmathematics.com</provider_url><author_name>Rajarshi Dey</author_name><author_url>https://soulofmathematics.com/index.php/author/rajarshidey1729gmail-com/</author_url><title>LAGRANGE'S EQUATION - SOUL OF MATHEMATICS</title><type>rich</type><width>600</width><height>338</height><html>&lt;blockquote class="wp-embedded-content" data-secret="KUWPkLVF8U"&gt;&lt;a href="https://soulofmathematics.com/index.php/lagranges-equation/"&gt;LAGRANGE&#x2019;S EQUATION&lt;/a&gt;&lt;/blockquote&gt;&lt;iframe sandbox="allow-scripts" security="restricted" src="https://soulofmathematics.com/index.php/lagranges-equation/embed/#?secret=KUWPkLVF8U" width="600" height="338" title="&#x201C;LAGRANGE&#x2019;S EQUATION&#x201D; &#x2014; SOUL OF MATHEMATICS" data-secret="KUWPkLVF8U" frameborder="0" marginwidth="0" marginheight="0" scrolling="no" class="wp-embedded-content"&gt;&lt;/iframe&gt;&lt;script type="text/javascript"&gt;
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</html><thumbnail_url>https://i0.wp.com/soulofmathematics.com/wp-content/uploads/2020/09/Heat.gif?fit=960%2C763&amp;ssl=1</thumbnail_url><thumbnail_width>960</thumbnail_width><thumbnail_height>763</thumbnail_height><description>As long as algebra and geometry have been separated, their progress have been slow and their uses limited; but when these two sciences have been united, they have lent each mutual forces, and have marched together towards perfection. Joseph-Louis Lagrange Partial differential equations can be formed by the elimination of arbitrary constants or arbitrary functions. If we have f (x, y) then we have the following representation of partial derivatives, Let F (x,y,z,p,q) = 0 be the first order differential equation. It contains three types of variables, where x and y are independent variables and z is dependent variable. A short classification of partial differential equations (PDE) &#x2013; Linear equation. A first order equation f (x, y, z, p, q) = 0 is known as linear if it is linear in p, q and z, that is, if given equation is of the form P(x, y) p + Q(x, y) q = R(x, y) z + S(x, y).For example, yx2p + xy2q = xyz + x2y3 and p + q = z + xy are both first order linear partial differential equations.Semi-linear equation. A first order partial differential equation f (x, y, z, p, q) = 0 is known as a semi-linear equation, if it is linear in p and q and the coefficients of p and q are functions of x and y only i.e. if the given equation is of the form P(x, y) p + Q(x, y) q = R(x, y, z)For example, xyp + x2yq = x2y2z2 and yp + xq = (x2z2/y2) are both first order semi-linear partial differential equations.Quasi-linear equation. A first order partial differential equation f(x, y, z, p, q) = 0 is known as quasi-linear equation, if it is linear in p and q, i.e., if the given equation is of the form P(x, y, z) p + Q(x, y, z) q = R(x, y, z)For example, x2zp + y2zp = xy and (x2 &#x2013; yz) p + (y2 &#x2013; zx) q = z2 &#x2013; xy are first order quasi-linear partial differential equations.Non-linear equation. A first order partial differential equation f(x, y, z, p, q) = 0 which does not come under the above three types, in known as a non-liner equation.For example, p2 + q2 = 1, p q = z and x2 p2 + y2 q2 = z2 are all non-linear partial differential equations. THE EQUATION A particular Quasi-linear partial differential equation of order one is of the form Pp + Qq = R, where P, Q and R are functions of x, y, z. Such a partial differential equation is known as Lagrange equation.For Example xyp + yzq = zx is a Lagrange equation. Theorem. The general solution of Lagrange equation Pp + Qq = R, is where &#x424; is an arbitrary function and u(x, y, z) = c1 and v(x, y, z) = c2 are two independent solutions of (dx)/P = (dy)/Q = (dz)/R. Here, c1 and c2 are arbitrary constants and at least one of u, v must contain z. Proof. Lets number the equations for simplification. Pp + Qq = R &#x424;(u, v) = 0 u(x, y, z) = c1 and v(x, y, z) = c2 (dx)/P = (dy)/Q = (dz)/R Differentiating (2) partially w.r.t. &#x2018;x&#x2019; and &#x2018;y&#x2019;, we get equations 5 and 6, Eliminating &#x2202;&#x424; / &#x2202;u and &#x2202;&#x424;/ &#x2202;v between (5) and (6), we have, Hence, (2) is a solution of this equation. Taking the differentials of u(x, y, z) = c1 and v(x, y, z) = c2, we get, As u and v are independent functions, the ratios dx : dy : dz, gives Comparing equations we obtain, We can imply that, Substituting these values we get, k(Pp + Qq) = kR or Pp + Qq = R, which is the given equation (1). Therefore, if u(x, y, z) = c1 and v(x, y, z) = c2 are two independent solutions of the system of differential equations (dx)/P = (dy)/Q = (dz)/R, then &#x424;(u, v) = 0 is a solution of Pp + Qq = R, &#x424; being an arbitrary function. Equations (4) are called Lagrange&#x2019;s auxillary (or subsidiary) equations for (1). Steps for solving Pp + Qq = R by Lagrange&#x2019;s method. Step 1. Put the given linear partial differential equation of the first order in the standard formPp + Qq = R. &#x2026;(1)Step 2. Write down Lagrange&#x2019;s auxiliary equations for (1) namely,(dx)/P = (dy)/Q = (dz)/R &#x2026;(2)Step 3. Solve equation (2). Let u(x, y, z) = c1 and v(x, y, z) = c2 be two independent solutions of (2).Step 4. The general solution (or integral) of (1) is then written in one of the following three equivalent forms :&#x424;(u, v) = 0, u = &#x424;(v) or v = &#x424;(u), &#x424; being an arbitrary function. FOR TUTORIAL SHEETS AND REFINED MATERIALS SUBSCRIBE TO RECEIVE THEM VIA EMAIL. IMAGE COURTESY</description></oembed>
